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Thread: Random DSP

  1. #1
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    Random DSP

    Hi, I have question about the following attachment.

    I have to sketch ACF of the output response.

    I know that I have to cross multiply and sum the terms to get the output sequence. I have followed through examples and I cant get it working and I am not sure where am I going wrong. Can someone shed some light please?

    I have worked out j(m) as 1,-4,6,-4,1

    i now need to work out output sequence and not sure how
    Attached Thumbnails Attached Thumbnails Random DSP-acf.jpg  
    Last edited by kpon; Oct 18th 2016 at 05:58 AM.
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  2. #2
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    Re: Random DSP

    you can't solve for the output sequence. It's random.

    What you can do is find the ACF of the output process directly using a double convolution of the input ACF with the impulse response

    or probably easier find the frequency response of the impulse respose and take it's squared magnitude.

    Multiply that by the ACF of the input process (the graph on the right)

    Then bring that back to the discrete time domain with an inverse transform.

    That will be the ACF of the output process.
    Thanks from topsquark
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  3. #3
    Forum Admin topsquark's Avatar
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    Re: Random DSP

    Ummmm... yeah. Whatever romsek said.

    -Dan
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