Get everything on one side of the inequality:

Now find the critical points. These are where either the numerator or denominator are 0. I get as critical points.

Now break the number line into sections based on these critical points:

and

and

Now test the inequality on each of these intervals:

: ? Yes.

: ? No.

: ? Yes.

So the final solution set is . (I have included the 16/3 point because this does also satisfy the inequality. If we had < in the inequality we would not do this. We can't include 8 in the solution set because the original expression doesn't exist at x = 8.)

You could also see this by graphing. See the graph below.

-Dan