Thread: [SOLVED] Miscellaneous 6 OCR

Hi everyone, I am new in this forum. Anyway I have been struggling with an inequality question in my homework, unfortunately due in tomarrow.

Find the value of k for the following equation which has 2 real roots

Kx^2 + kx + 2 = 0

Now I have found that: b^2 -4ac
k^2 - 4*k*2> 0
K^2 -8k > 0

I do not understand what to do after this stage because it is not possible to expand the brackets or square root the 8

Originally Posted by james singh jagjit

Hi everyone, I am new in this forum. Anyway I have been struggling with an inequality question in my homework, unfortunately due in tomarrow.

Find the value of k for the following equation which has 2 real roots

Kx^2 + kx + 2 = 0

Now I have found that: b^2 -4ac
k^2 - 4*k*2> 0
K^2 -8k > 0

I do not understand what to do after this stage because it is not possible to expand the brackets or square root the 8

Thus

---0_________8---





---
Thanks for the spot Jhevon!

Hello, James!

Welcome aboard!

Find the value of for which the following equation
has two real roots: .

Now I have found that: .

So we have: .

Factor: .

It says: The product of two numbers is positive.
When does this happen?
. . It happens in two ways . . .

[1] Both factors are positive: .

[2] Both factors are negative: .


Therefore, the equation has two real roots for: .