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Math Help - newton raphson method

  1. #1
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    newton raphson method

    given f(x)=c where c is a real valued constant f(x)=cos(x) when mod(x)<=1 and f(x)=cos(x)+(x^2-1)^2 when mod(x)>=1

    for a given c show that x(n)=(-1)^n, where x(0)=1

    also discuss the convergence of this approximation

    i applied the newton raphson method but not getting anywhere near x(n)=(-1)^n
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  2. #2
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    Re: newton raphson method

    The Newton-Raphson method is a method for calculating roots of non-linear equations.
    Exactly what non-linear equation are you trying to solve ?
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  3. #3
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    Re: newton raphson method

    f(x)=cos(x)+(x^2-1)^2 is the function
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  4. #4
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    Re: newton raphson method

    Fine, but what does f (x)=c and x (n)=(-1)^n have to do with it ? I'll have a look at it.
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  5. #5
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    Re: newton raphson method

    ?? The f(x) that you give is never zero. Try again.
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  6. #6
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    Re: newton raphson method

    is the question wrong then
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  7. #7
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    Re: newton raphson method

    The question as stated in #1 didn't seem to make much sense, I would be guessing as to what was meant, and the function you give in #3 doesn't have any zeros to calculate.
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  8. #8
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    Re: newton raphson method

    is Newton Raphson similar to an epsilon perturbation method and maybe less accurate? you can program these into software
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