# newton raphson method

• Feb 14th 2014, 05:54 AM
prasum
newton raphson method
given f(x)=c where c is a real valued constant f(x)=cos(x) when mod(x)<=1 and f(x)=cos(x)+(x^2-1)^2 when mod(x)>=1

for a given c show that x(n)=(-1)^n, where x(0)=1

also discuss the convergence of this approximation

i applied the newton raphson method but not getting anywhere near x(n)=(-1)^n
• Feb 14th 2014, 01:20 PM
BobP
Re: newton raphson method
The Newton-Raphson method is a method for calculating roots of non-linear equations.
Exactly what non-linear equation are you trying to solve ?
• Feb 14th 2014, 07:19 PM
prasum
Re: newton raphson method
f(x)=cos(x)+(x^2-1)^2 is the function
• Feb 15th 2014, 12:06 AM
BobP
Re: newton raphson method
Fine, but what does f (x)=c and x (n)=(-1)^n have to do with it ? I'll have a look at it.
• Feb 16th 2014, 04:57 AM
BobP
Re: newton raphson method
?? The f(x) that you give is never zero. Try again.
• Feb 16th 2014, 07:46 AM
prasum
Re: newton raphson method
is the question wrong then
• Feb 16th 2014, 12:24 PM
BobP
Re: newton raphson method
The question as stated in #1 didn't seem to make much sense, I would be guessing as to what was meant, and the function you give in #3 doesn't have any zeros to calculate.
• Feb 16th 2014, 01:49 PM
mathnerd15
Re: newton raphson method
is Newton Raphson similar to an epsilon perturbation method and maybe less accurate? you can program these into software