Determine all the possible values where 0 degree <= x <= 360 degree such that; sin x sec x - 3 sin x = 0
Follow Math Help Forum on Facebook and Google+
Hey choi105. Please show us what you have tried.
sin x sec x - 3 sin x = 0 sin x 1/cos x - 3 sin x = 0 sin x - 3 sin x = cos x then i not sure the step correct or not...
Hint: Try thinking in terms of tan(x).
Originally Posted by choi105 sin x sec x - 3 sin x = 0 sin x 1/cos x - 3 sin x = 0 sin x - 3 sin x = cos x then i not sure the step correct or not... First of all, your third line is incorrect, since when you multiply everything through by you're supposed to get . Anyway, you should factorise the entire expression first and set each factor equal to 0. Go from here...
View Tag Cloud