A diver of mass 60 kg, on entering water with an initial velocity of 15.35 ms-1, experiences a force of resistance, due to the water opposing motion, of magnitude 180v Newtons, where v is the velocity of the diver in ms-1. In addition to the force of gravity, the diver also experiences a constant upward buoyancy force of 720 N. Take the origin of motion to be at the surface of the water. The magnitude g of the acceleration due to gravity can be taken as 10 ms-1.
Calculate the maximum depth, in metres, the diver will submerge. Give your answer to 3 decimal places.
The answer is 4.41. Can anyone show me the workings? :'(