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**weijing85** A diver of mass 60 kg, on entering water with an initial velocity of 15.35 ms^{-1, }experiences a force of resistance, due to the water opposing motion, of magnitude 180v Newtons, where v is the velocity of the diver in ms^{-1}. In addition to the force of gravity, the diver also experiences a constant upward buoyancy force of 720 N. Take the origin of motion to be at the surface of the water. The magnitude g of the acceleration due to gravity can be taken as 10 ms^{-1. }

Calculate the maximum depth, in metres, the diver will submerge. Give your answer to 3 decimal places.

The answer is 4.41. Can anyone show me the workings? :'(

Rgds, Bruce