A common (and I believe incorrect) answer to the problem takes the form of treating both coins as if they are fair coins, and then creating a table like so:I flipped a fair coin twice, and I can tell you about one of them: It was a head. What are the chances I got two heads?
P(Head) = 1/2 P(Tail) = 1/2 P(Head) = 1/2 1/2 * 1/2 = 1/4 1/2 * 1/2 = 1/4 P(Tail) = 1/2 1/2 * 1/2 = 1/4 N/A
So according to this model, there are 3/4 chances with a head, 1/4 Head-Head and 2/4 Head-Tail. But the probabilities don't add up to 1, because we aren't including the impossible 1/4 Tail-Tail, which should set off some warning bells.
I suggest the knowledge that one of them is a head is being handled incorrectly. I believe that knowing one of them is a head is equivalent to altering the probability of one of the two coins to be Head:1 and Tail:0. Or to put it another way, every run of an experiment would result in "one of them is a head" being a true statement.
With this perspective on what it means to know one of them is a head, we can construct a different probability table, like so:
P(Head) = 1/2 P(Tail) = 1/2 P(Head) = 1 1 * 1/2 = 1/2 1 * 1/2 = 1/2 P(Tail) = 0 0 * 1/2 = 0 0 * 1/2 = 0