Hi please help me with this! How do I do part b!

I thought to find the midpoint of B and the negative y-axis, and then equate the y-coordinate to sqrt(14) but that did not seem to be the way..

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- Feb 1st 2013, 09:41 PM #1

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- Feb 1st 2013, 11:27 PM #7

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## Re: Need help with vectos

I just went to search online,

they said a is the left right distance, b is the front back distance and c is the up down distance.

I understand why a^2 + b^2 + c^2 = d^2 but then shouldn't a be -1, b be -1, and c be 2?

How did you know sqrt 14 is the distance? The more I look at the diagram, it looks like the midpoint!

- Feb 1st 2013, 11:33 PM #8

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- Feb 1st 2013, 11:41 PM #9

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- Feb 1st 2013, 11:43 PM #10

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- Feb 1st 2013, 11:48 PM #11

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- Feb 1st 2013, 11:50 PM #12

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- Feb 2nd 2013, 12:17 AM #13

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- Feb 2nd 2013, 12:20 AM #14

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- Feb 2nd 2013, 12:27 AM #15

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