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- Jan 1st 2013, 08:22 PM #1

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- Jan 1st 2013, 10:07 PM #2

- Jan 1st 2013, 11:07 PM #3
## Re: 6÷2(1+2)=?

Watch this guy explain with a similar problem ( 48÷2 (9+3) ) :

Berkeley Ring Theorist Solves 48 ÷ 2(9+3) - YouTube

In a nutshell, the problem is ambiguous and nothing more than a troll.

- Jan 1st 2013, 11:18 PM #4

- Jan 2nd 2013, 12:40 AM #5

- Jan 2nd 2013, 01:09 AM #6

- Jan 2nd 2013, 07:19 AM #7

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- Jan 2013
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## Re: 6÷2(1+2)=?

See, I got 1 as my answer, but I've been away from school for 12+ years so...I'd ask for a second and third opinion. This is how I got it:

6/2(1+2) ------> At some point I was taught that anything in parenthesis is always done first, which means this would be next:

6/2(3) -------> multiplication is supposed to follow so then:

6/6 and..

1 tada!!

But like I said, I've been out of school for way too long. I hope this helps and if needed, please correct me.

- Jan 2nd 2013, 07:27 AM #8
## Re: 6÷2(1+2)=?

Multiplication and division are done with the same precedence from left to right, so we would have:

6/2(1+2) = 6/2(3) = 3(3) = 9

If we wish for the division to be done first, then we would write:

6/(2(1+2))

As it has been given though, is the same as:

(6/2)(1+2)

- Jan 2nd 2013, 07:30 AM #9