z = (-i) ^1/3
z^3 = -i
let z = re ^i ϴ
z^3 = (r^3)(e^i3ϴ) - i = e ^i[(3π/2) + 2nπ]
pls help me to understand how to find "3ϴ"?
what is the formula to find 3ϴ??
Unfortunately, Latex does not seem to be working today. I have removed the Latex tags.
Just what you wrote: 3ϴ= [(3π/2) + 2nπ]The exponential form of complex number
z = (-i) ^1/3
z^3 = -i
let z = re ^i ϴ
z^3 = (r^3)(e^i3ϴ) - i = e ^i[(3π/2) + 2nπ]
pls help me to understand how to find "3ϴ"?
what is the formula to find 3ϴ??
Now, solve for ϴ.