substitute a=2A+1,b=2B+1,c=2C+1 d=2D+1 and consider the number of non negative integer solutions of A+B+C+D=4.
Hey I need some help with this problem:
How many solutions in natural numbers are there to the equation a + b + c + d = 12 where a and b are odd?
I am hoping someone can show me the steps on how to go about doing this so I will understand how to do this problem thanks.
You should note that the OP requires only a & b be odd.
Look at the coefficient of in this expansion.