Hello, gfbrd!
I'm familiar with this type of problem,
but this one took me a couple of tries . . .
Square [1]: .
. .
. .
Hence: .
Cube [1]: .
. .
Add to both sides:
. .
The left side is:
. .
. . . .
. .
. .
Therefore: .
Hey there sorry if this is in the wrong thread, but I need some help with this problem
If x^2+y^2+z^2=49, and x+y+z=x^3+y^3+z^3=7
find xyz
I've been trying this problem for a while now and was hoping if someone can guide me through this problem so I can understand it better thanks.