Hello everyone, i need some help on this question :
By using the Maclauriw series, show that the first three terms of the expansion ln[sec(2x)+tan(2x)] in powers of x are 2x + [4(x^3)]/3 + [4(x^5)]/3.
Thanks!
Hello everyone, i need some help on this question :
By using the Maclauriw series, show that the first three terms of the expansion ln[sec(2x)+tan(2x)] in powers of x are 2x + [4(x^3)]/3 + [4(x^5)]/3.
Thanks!
It will be easiest if you find the MacLaurin Series for $\displaystyle \displaystyle \begin{align*} \sec{(2x)} \end{align*}$ and integrate it, since $\displaystyle \displaystyle \begin{align*} \int{\sec{(2x)}\,dx} = \ln{\left[ \sec{(2x)} + \tan{(2x)} \right]} \end{align*}$.
Are you saying that you do not know what the MacLaurin series is? The MacLaurin series for function f is the Taylor's series about x= 0. It's first three terms are f(0)+ f'(0)x+ f''(0)x^2/2. So the first thing you need to do is find the first and second derivatives of ln[sec(2x)+ tan(2x)] and evaluate at x= 0. Tedious, but nothing deep.