• Oct 31st 2012, 02:20 PM
mikejohn
Hello Guys

I wonder if anyone can help me solving the attached question if possible by detailed steps.

Mike
• Oct 31st 2012, 06:44 PM
chiro
Hey mikejohn.

Can you show us what you have tried. As a starting hint, remember something is perpendicular if <a,b> = 0 and each line has a direction vector so in order to be perpendicular, both direction vectors must be orthogonal.

In terms of number 2, remember that an intersection is just when one thing equals another. What is the definition of the x-z plane in equation form? How can you make them equal one another and find a solution?

For number 3, you have the area of a triangle using normal high school math (something like 1/2absin(C) where a and b are the lengths and sin(C) is the angle formed between those lines) so |AB| = a and |AC| = b.
• Oct 31st 2012, 07:54 PM
mikejohn
Quote:

Originally Posted by chiro
Hey mikejohn.

Can you show us what you have tried. As a starting hint, remember something is perpendicular if <a,b> = 0 and each line has a direction vector so in order to be perpendicular, both direction vectors must be orthogonal.

In terms of number 2, remember that an intersection is just when one thing equals another. What is the definition of the x-z plane in equation form? How can you make them equal one another and find a solution?

For number 3, you have the area of a triangle using normal high school math (something like 1/2absin(C) where a and b are the lengths and sin(C) is the angle formed between those lines) so |AB| = a and |AC| = b.

Thanks so much for giving me some hints.
But to be honest, the questions still vague for me, unfortunately because I did not understand the vector, lines, and planes topics from the professor and I do not have neither time right now to navigate through all the stuff that he gave us nor surfing internet to understand these topics

I would really really appreciate your time of further help with detailed steps if possible.
• Oct 31st 2012, 08:01 PM
chiro