# Thread: Heaviside

1. ## Heaviside

Answer

f(t) = 7H(t) + bH(t-5)

when t = 5
f(5) = 49 + 7b
15 = 49 + 7b
-34 = 7b
b = -34/7

Is it correct?

Report Abuse

2. ## Re: Heaviside

Originally Posted by mathsforumhelp

Answer

f(t) = 7H(t) + bH(t-5)

when t = 5
f(5) = 49 + 7b
15 = 49 + 7b
-34 = 7b
b = -34/7

Is it correct?

Report Abuse
No. Did you plug your answer back into the original equation?

Remember that $H(t-a)=\begin{cases} 0, \quad t < a \\ 1, \quad t > a\end{cases}$

You should find that $b=8$