Hey I need some help with this math problem.
Find a formula for the nth term of the sequence
1, 2, 2, 3, 3, 3, 4, 4, 4, 4, 5, 5, 5, 5, 5, ...
I can see the pattern, but I'm not sure how to go about finding a formula for this sequence. Hoping someone can guide me through this problem so I can understand it better thanks.
The term in the interval (n(n-1)/2, n(n+1)/2]is n. The pattern generalizes as follows: The first term is 1, the next two terms is 2, etc... (as you already know). So, every number (k) repeats k times, and the successive terms increase by 1, after repetition, starting from 1. It means, the nth term has to do with how many numbers are below it, and since each number repeats itself "its value" number of times, this has to do with sum of first n numbers. Once you cross, sum of first n numbers terms, you get a new value for the term in the series.
Salahuddin
Maths online
The term in the interval (n(n-1)/2, n(n+1)/2]is n. Doesnt that give a formula?
Salahuddin
Maths online
The triangular numbersOriginally Posted by gfbrd
are places in your sequence where the terms "change". That is, from the
term to the
term the sequence terms are
and
gives the fourth triangular number. The floor function gives an integer. From terms
at term
it changes to
for the next six terms.
  |
2Thanks
LinkBack URL
About LinkBacks