Results 1 to 2 of 2

Math Help - Periodic extension

  1. #1
    Newbie
    Joined
    Oct 2009
    Posts
    24

    Periodic extension

    Periodic extension-screen-shot-2012-10-26-12.58.15-pm.png

    The periodic extension will have value at 1 which is half way the value as you approach 1 from the left (which is 13) and as you approach one from the right (which is 1)

    That average value is 7.

    FSf(1) = 7 is the answer. Can someone check whether I am right or wrong.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    Joined
    Sep 2012
    From
    Australia
    Posts
    3,607
    Thanks
    591

    Re: Periodic extension

    Hey mathsforumhelp.

    The value at discontinuities will be the average of the two values and is pointed out here:

    Gibbs phenomenon - Wikipedia, the free encyclopedia

    They specify this in terms of F(x) = [f(x-) + f(x+)]/2 where F(x) is the fourier series representation f(x-) = f(1-) = 13*1 = 13 and f(x+) = f(1+) = 1 so (13+1)/2 = 14/2 = 7.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 2
    Last Post: July 2nd 2012, 11:40 AM
  2. Prove that an extension is a continuous extension
    Posted in the Differential Geometry Forum
    Replies: 2
    Last Post: August 12th 2011, 05:50 AM
  3. Replies: 0
    Last Post: September 12th 2010, 12:51 PM
  4. periodic
    Posted in the Differential Geometry Forum
    Replies: 3
    Last Post: November 30th 2009, 06:13 PM
  5. Quick Periodic Extension Question
    Posted in the Pre-Calculus Forum
    Replies: 2
    Last Post: September 27th 2009, 12:09 PM

Search Tags


/mathhelpforum @mathhelpforum