Suppose f,g, & h are defined on (a,b) & a<x0<b. Assume f and h are differentiable at x0, f(x0)=h(x0), & f(x)<g(x)<h(x) for all x in (a,b). Prove that g is differentiable at x0 and f'(x0)=g'(x0)=g'(x0).

Printable View

- October 22nd 2012, 09:58 AMfraniosProve
Suppose f,g, & h are defined on (a,b) & a<x0<b. Assume f and h are differentiable at x0, f(x0)=h(x0), & f(x)<g(x)<h(x) for all x in (a,b). Prove that g is differentiable at x0 and f'(x0)=g'(x0)=g'(x0).

- October 22nd 2012, 10:33 AMPlatoRe: Prove