using the alternating series test,I have found that the Leibnitz series converges to zero.but is it sufficient for us to say that the sin of that series converges to zero???
please help me to find the answer for the following problem immediately...
limit (sin(sigma k from 1 to infinity)(-1)^k+1/2k-1)) as n goes to infinity.
basically find the limit of SIN(Leibniz formula) as k goes to infinity.