# limit of sequences and series-real analysis

• October 18th 2012, 05:17 PM
chath
limit of sequences and series-real analysis

limit (sin(sigma k from 1 to infinity)(-1)^k+1/2k-1)) as n goes to infinity.

basically find the limit of SIN(Leibniz formula) as k goes to infinity.
• October 18th 2012, 05:38 PM
chath
Re: limit of sequences and series-real analysis
using the alternating series test,I have found that the Leibnitz series converges to zero.but is it sufficient for us to say that the sin of that series converges to zero???
• October 18th 2012, 07:58 PM
TheEmptySet
Re: limit of sequences and series-real analysis
Quote:

Originally Posted by chath

limit (sin(sigma k from 1 to infinity)(-1)^k+1/2k-1)) as n goes to infinity.

basically find the limit of SIN(Leibniz formula) as k goes to infinity.

I think this is what you are asking.

$\lim_{k \to \infty} \sin \left( \sum_{k=1}^{\infty} \frac{(-1)^{k+1}}{2k-1} \right)$

Since the sine function is continous, the limit can be moved \lim_{k \to \infty} inside the function.

The sum inside it the infinite series for the arctangent function evaluated at 1.

The $\tan^{-1}(1)=\frac{\pi}{4}$

$\sin \left(\lim_{k \to \infty} \sum_{k=1}^{\infty} \frac{(-1)^{k+1}}{2k-1} \right)=\sin\left( \frac{\pi}{4}\right)=\frac{1}{\sqrt{2}}$