The problem has 5 parts and is based on:

Let f,g L^2(T, dx). Define the convolution of the two functions by: (f ** g)(x) = 1/(2pi)

a) Prove that f**g is a continuous function.

b) Prove that f**g = g**f

c) Denote by h(n) = 1/(2pi) the Fourier coefficients of a function h L^2(T, dx). Prove that f(*^*g)(n) = , n Z

d) Deduce that, for three functions in L^2: f**(g**h) = (f**g)**h.

e) Is there a function e L^2(T, dx) with the property: e*f = f, f L^2(T,dx)?

Where ** is the convolution symbol and T = {z such that |z| = 1} = { | t [0, 2pi]}

Any help at all will be amazing. I have no idea what is going on.