standard kinematics equation with constant acceleration ...
, ,
use the quadratic formula to solve for t in hours ... calculate the dino's speed using your calculated time and the distance it traveled.
Hello all, first post so I'll try to be as clear as possible. I'm doing some revision for a University exam, and I have been trying to learn about trigonometry and some complementry equations for Vector explaination in 2D.
I've managed to figure out the trig suff so I have the tools but not the knowledge to figure the rest out. Here is my question:
A Dinosaur is running scared as Meteors fall onto the Earths surface, at a given point his life becomes in peril as one Meteor looms over head and may well be set to directly collide with our fearful lizard friend.
- The Dinosaur is travelling at a constant velocity of "X"km/h.
- The Meteor is travelling at an initial velocity of 100km/h and is accelerating at 2km/h^{2}.
- As it happens we know where the meteor hits and sadly the Dinosaur is struck after having travelled 200km. (yes I know the distance is rather unbelievable)
- The Meteor started directly above our x-dino friend stationed 200km above it, before hitting the dinosaur, trigonometry says that the meteor had travelled 282.885km.
Here are the questions;
- how long did it take the meteor to travel 282.885km?
- and using that time how fast was the dinosaur going to have been so unlucky?
The difficulty comes from the meteor not just having a velocity but also acceleration.