Prove that set of all limit points is closed?

Hey guys,

If A is a subset of R, let L be the set of all limit points. We want to show that L is closed. Here's how I was thinking about proving it:

To show that L is closed, we can show that the complement of L (call it c(L)) is open. c(L) is open if we can put an epsilon-neighborhood around each of the isolated points of L and always have it included in L. I'm not exactly sure where to go from here.

Any hints would be much appreciated.

Thanks,
Mariogs

Quote:

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Originally Posted by mariogs379

If A is a subset of R, let L be the set of all limit points. We want to show that L is closed. Here's how I was thinking about proving it: To show that L is closed

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Surely you mean that is the set of all limit points of
That is usually called the derived set of and is noted by
Now if then is not a limit point of .
So there is open set such that .
Can finish?

Yeah, that's what I meant. So Qt must be open and, because it is the complement of L, L must be closed. Yeah?