A copper bottomed sauce pan contained 0.800L of boiling water boils dry in 12.0 min. Assuming that all the heat is transferred through the flat copper bottom, which has a diameter of 15.0cm and a thickness of 3.70mm, calculate the temperature difference between the inside and outside of the copper bottom while some water is still in the pan.

I have no idea how I'm supposed to solve this. I have been calculating whatever I can out of the data, though which I will provide here, but be cautious because my calculations could be wrong.

Volume of Copper Pan bottom = (0.075^2)(pi)(0.0037) = 6.538 * 10^-5 cubic meters

Latent heat of evaporation of water = 2257 kJ/kg provided by engineertoolbox

mass of initial water= 0.800 kg

c_copper = 0.39 kJ/(kg*K) *provided by engineertoolbox*

power = (2257*0.800)/(12*60) = 2.507777 kW

energy required to evaporate 0.800kg of water = 0.800 * 2257 = 1805KJ