Thread: annoying relativity

I am having problems with an equation involving relativity, but my question is directly math related currently the equation is in the form of e=mc^2(blah blah blah), but I need it in the form e=mv^2(blah blah blah).

the current equation is "E=mc^2((1/(sqrt(1-v^2/c^2)))-1"

where sqrt(x) signifys the square root of x. please help.

what I really need is the answer, but I would love to know the steps taken.

Originally Posted by dented42

I am having problems with an equation involving relativity, but my question is directly math related currently the equation is in the form of e=mc^2(blah blah blah), but I need it in the form e=mv^2(blah blah blah).

the current equation is "E=mc^2((1/(sqrt(1-v^2/c^2)))-1"

where sqrt(x) signifys the square root of x. please help.

what I really need is the answer, but I would love to know the steps taken.

I do not understand you want to solve for ?

Originally Posted by dented42

I am having problems with an equation involving relativity, but my question is directly math related currently the equation is in the form of e=mc^2(blah blah blah), but I need it in the form e=mv^2(blah blah blah).

the current equation is "E=mc^2((1/(sqrt(1-v^2/c^2)))-1"

where sqrt(x) signifys the square root of x. please help.

what I really need is the answer, but I would love to know the steps taken.

What you want to do is expand the gamma function ( ) in a Taylor series about v=0. So . You should get .

-Dan