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why does lim(z→e^(πi/4)) (z - e^(πi/4))/(1 + z^4) = lim(z→e^(πi/4)) 1/(4z^3)
Quote: Originally Posted by blueyellow why does lim(z→e^(πi/4)) (z - e^(πi/4))/(1 + z^4) = lim(z→e^(πi/4)) 1/(4z^3) L'Hospital's Rule.
