Could you please explain aswell as giving me the answer, thanks (=
The archivist misplaced his shopping list inside one of the books. He has a handy way to remember which volume he placed it in, though. The volume number was a four-digit number, in which all four digits were unique. If you take the largest possible four-digit number that can be made by rearranging the four digits, and you subtract from that the smallest possible four-digit number that can be made by rearranging the four digits, the number you get is volume number, but with the digits in reverse order.
In what volume of the Encyclopedia Altadoria did he leave his shopping list?
Using what you described there is no way to find the volume directly.
However, if you mean that the largest possible 4 digit number that any book in the library can be (with all unique digits) then that would be 9876 (because 9950 has 2 x 9), and we want the largest we can obtin so make each digit 1 smaller than the last. The smallest possible would be 0123.
If this is correct then all you do is subtract the smaller from the larger, reverse the digits and get the volume.
However if you mean what you say exactly, it's not possible to work out directly (i think) because the volume number is unknown, the largest and smallest could be any one of many many permutations.
The solution to this problem is 4716
The largest number obtained from rearranging the digits is 7641
The smallest number obtained from rearranging the digits is 1467
Subtract the smaller from the larger to get 6174
Reverse the order of 6174 and you get 4716 which is the number we started with. Interestingly there is only one number between 0000 and 9999 that has this property.
You could say I cheated to get this answer as I wrote a BASIC algorithm to solve it by trial and error. I have posted the program below, with hopefully enough comments to make it self explanatory. The challenge now is to discover if there is a logical or algebraic method to solve this question without needing to resort to a computer.
REM ***** BASIC *****
Sub Main
Dim N(4),P(4),T(4),RT(4) As Integer
For i = 0 to 9950
digitize(i,N()) Rem Split i into 4 digits stored in array N().
If isunique(N()) then
largest(N()) Rem If all the digits are unique then rearrange to find the largest number.
NN=N(1)*1000+N(2)*100+N(3)*10+N(4) Rem NN is the value of the largest number express as a single variable.
P(1)=N(4) : P(2)=N(3) : P(3)=N(2) : P(4)= N(1) Rem Reverse the digits of N to find the smallest value.
PP=P(1)*1000+P(2)*100+P(3)*10+P(4) Rem PP is the smallest value.
TT=NN-PP
digitize(TT,T()) Rem Subtract smallest from largest, digitise it and reverse the digits.
RT(1)=T(4) : RT(2)=T(3) : RT(3)=T(2) : RT(4)= T(1)
NT=RT(1)*1000+RT(2)*100+RT(3)*10+RT(4) Rem Find the actual value of the reversed digits.
If NT=i then
Print "Found a solution ";i;" ";NN;" -";PP;"=";TT;" <--> ";NT
end if
end if
next i
msgbox "No more solutions"
end Sub
Sub digitize(ii,Q())
k=ii
Q(1)=Fix(k/1000) : k= k-Q(1)*1000
Q(2)=Fix(k/100) : k= k-Q(2)*100
Q(3)=Fix(k/10) : k= k-Q(3)*10
Q(4)=k
end sub
Function isUnique(Q()) as boolean
For j=1 to 4
For k=j+1 to 4
If Q(j)=Q(k) then
isUnique = false
exit function
end if
next k
next j
isUnique=true
end function
Sub reverse_digits(Q(),R())
R(1)=Q(4) : R(2) =Q(3) : R(3)=Q(2) : R(4)= Q(1)
end sub
Sub largest(Q())
For j=2 to 4
For k = j to 4
If Q(k)>Q(j-1) then
temp = Q(j-1) : q(j-1)=q(k) :Q(k)=temp
end if
next k
next j
end sub
Hello, kirsty_b!
The archivist misplaced his shopping list inside one of the books.
He has a handy way to remember which volume he placed it in, though.
The volume number was a four-digit number, in which all four digits were unique.
If you take the largest possible four-digit number that can be made
by rearranging the four digits, and you subtract from that the smallest
possible four-digit number that can be made by rearranging the four digits,
the number you get is volume number, but with the digits in reverse order.
In what volume of the Encyclopedia Altadoria did he leave his shopping list?
One possible answer: .
The largest permutation is:
The smallest permutation is:
The difference is: .
Hence, the volume number is .
Are there any other solutions? . . . I don't know.