Solve $\displaystyle 3x=(x+3)(ln(x+1))$

how do i solve this equation?

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- Mar 30th 2011, 01:22 AMmechaniachelp with a equation
Solve $\displaystyle 3x=(x+3)(ln(x+1))$

how do i solve this equation? - Mar 30th 2011, 01:36 AMAckbeet
By inspection, and numerically. There appear to be two solutions. One is zero, which you can see by inspection. The other is approximately 7.57736, which you can get by a numerical routine. Here is WolframAlpha's answer.