Fourier transform of sinc(4t)

I'm preparing for an exam in the signals and systems class I'm taking. One of the practice exams has a problem that requires you to take the fourier transform of $\displaystyle sinc(4t)$. From a table of fourier transform pairs I found: $\displaystyle \frac{\omega_b}{\pi}sinc(\frac{\omega_b t}{\pi})\Rightarrow rect(\omega/2\omega_b)$. Using this I tried to match the given $\displaystyle sinc(4t)$ be rewriting it as $\displaystyle \frac{1}{4}\frac{4\pi}{\pi}sinc(\frac{4\pi t}{\pi})$. From this I get that $\displaystyle \omega_b = 4\pi$ and thus the fourier transform should yield $\displaystyle \frac{1}{4}rect(\omega/8\pi)$. But, in the exam solutions they show the fourier transform to yield $\displaystyle \frac{\pi}{4}rect(\omega/8)$. Any ideas where I'm going wrong? Thanks.