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Math Help - Question from a non-math-head

  1. #1
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    Question from a non-math-head

    I'm a photographer; I need to incorporate a "complex" math formula into a picture I'm creating and found the following at Math.com under "Complex Definitions of Functions and Operations" :

    tan(a + BI) = ( tan(a) + i tanh(b) ) / ( 1 - i tan(a) tanh(b))
    = ( sech 2(b)tan(a) + sec 2(a)tanh(b) i ) / (1 + tan 2(a)tanh 2(b))


    Rather than making an error in using something that makes little sense, I thought I'd ask here. I'm seeking something about that long. BTW, this is for a personal project about the level of awareness of math in children.


    Thanks, Ken
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  2. #2
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    Can you use something a bit more standard?
    \sin(a+bi)=\sin(a)\cosh(b)+i~\cos(a)\sinh(b)
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  3. #3
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    Say, thanks for the reply. I don't see why not, however, my curiosity begs the question:
    what's wrong with the equation I found? Are you suggesting that mere mortals might have a better grasp of what you sent? On that note, I'd say it would make no difference.
    Perhaps if I attach what I've created, you'll see what I mean:

    Question from a non-math-head-oriental-girl-math-around-globe_print.jpg
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  4. #4
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    There is nothing wrong with it.
    I just think that using something familiar to more people would be best.
    If you want a longer image here is another:
    z = a + bi\, \Rightarrow \,\cos (z) = \dfrac{{e^{iz}  + e^{ - iz} }}<br />
{2} = \cos (a)\cosh (b) - i\,\sin (a)\sinh (b)
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  5. #5
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    I just copied it over and will get to it tomorrow. It's appreciated. BTW, what does it reference? I more or less like to know what I'm doing!
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  6. #6
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    It called writing an elementary complex valued function in the u+i\,v form.
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  7. #7
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    Thanks, AND...I'm having a helluva time trying to write it out...can't figure how to have the squared iz's appear where they're supposed to and the numerator/denominator as well. It really needs to be imported in a higher res than I can get off the forum site page or I'll try a few fonts and other tricks but it may be a lost cause. More simply put it may not worth the trouble since you've acknowledged the formula I've got is not too bad. Again, I do appreciate the assistance. Ken
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