http://i839.photobucket.com/albums/z...wuceit/134.pngI solved this first in that this appears to be an inversion.

$\displaystyle \frac{\frac{V^2}{R_2}}{\frac{V^2}{R_1}}

\Rightarrow

\frac{I_1}{I_2}

\Rightarrow

\frac{[1+60(.005)]}{[1+60(.004)]}

\times

\frac{[1+10(.004)]}{[1+10(.005)]}

\Rightarrow

\frac{(1.3)(1.04)}{(1.24)(1.05)} = 1.0384

$

I still don't understand what these temperature coefficients mean. or why the have the $\displaystyle C^{-1}$

appreciate any comments...