Prove that if a set contains each of its accumulation points, then it must be a closed set.
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Prove that if a set contains each of its accumulation points, then it must be a closed set.
Suppose thatQuote:
Originally Posted by LCopper2010
is such a set.
If, the complement, then
is not a limit point of
Therefore, the is an open set,that contains no point of
Now show the complement is open.
What does this have to do with complex variables?