# Thread: two-var. equation

1. ## two-var. equation

how can i write and solve(plot) a one-variable equ. that consists of several one var. expressions?

for exaple:
(a0*z1^2+c0)+(a0*z1^2-c0)*cos(2*U0+m*Pi)+b0*z1*sin(2*U0+m*Pi)=0

is an equ. that a0 & b0 & c0 & z1 & U0 are all one variable equations that determined before.

2. Originally Posted by asfn
how can i write and solve(plot) a one-variable equ. that consists of several one var. expressions?

for exaple:
(a0*z1^2+c0)+(a0*z1^2-c0)*cos(2*U0+m*Pi)+b0*z1*sin(2*U0+m*Pi)=0

is an equ. that a0 & b0 & c0 & z1 & U0 are all one variable equations that determined before.
More explanation needed.

For instance are a0, ... expressions in z1 or a different variable?

Also what do you mean by plot and or solve?

CB

3. all af theme depend to beta.
for example:

lambda=constant, c=constant, m=0 or 1.
k=2Pi/lambda
u=(k^2-beta^2), z1=alpha/u, U0=k*u*c
all of a0,b0 and c0 coefficients are expressions of "beta",
and therefore the principle equation depend only to beta.

and i want to get zeros of that equ. for an interval of lamda in a "for" loop.

4. Originally Posted by asfn
all af theme depend to beta.
for example:

lambda=constant, c=constant, m=0 or 1.
k=2Pi/lambda
u=(k^2-beta^2), z1=alpha/u, U0=k*u*c
all of a0,b0 and c0 coefficients are expressions of "beta",
and therefore the principle equation depend only to beta.

and i want to get zeros of that equ. for an interval of lamda in a "for" loop.
So your equation is a quadratic in z1, and z1 is the variable for solution?

CB

5. My equation is a quadratic in z1,but when z1 is itself an equatin of beta, then the variable of the main equation is beta.