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Math Help - two-var. equation

  1. #1
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    two-var. equation

    how can i write and solve(plot) a one-variable equ. that consists of several one var. expressions?

    for exaple:
    (a0*z1^2+c0)+(a0*z1^2-c0)*cos(2*U0+m*Pi)+b0*z1*sin(2*U0+m*Pi)=0

    is an equ. that a0 & b0 & c0 & z1 & U0 are all one variable equations that determined before.
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by asfn View Post
    how can i write and solve(plot) a one-variable equ. that consists of several one var. expressions?

    for exaple:
    (a0*z1^2+c0)+(a0*z1^2-c0)*cos(2*U0+m*Pi)+b0*z1*sin(2*U0+m*Pi)=0

    is an equ. that a0 & b0 & c0 & z1 & U0 are all one variable equations that determined before.
    More explanation needed.

    For instance are a0, ... expressions in z1 or a different variable?

    Also what do you mean by plot and or solve?

    CB
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  3. #3
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    all af theme depend to beta.
    for example:

    lambda=constant, c=constant, m=0 or 1.
    k=2Pi/lambda
    u=(k^2-beta^2), z1=alpha/u, U0=k*u*c
    all of a0,b0 and c0 coefficients are expressions of "beta",
    and therefore the principle equation depend only to beta.

    and i want to get zeros of that equ. for an interval of lamda in a "for" loop.
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  4. #4
    Grand Panjandrum
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    Quote Originally Posted by asfn View Post
    all af theme depend to beta.
    for example:

    lambda=constant, c=constant, m=0 or 1.
    k=2Pi/lambda
    u=(k^2-beta^2), z1=alpha/u, U0=k*u*c
    all of a0,b0 and c0 coefficients are expressions of "beta",
    and therefore the principle equation depend only to beta.

    and i want to get zeros of that equ. for an interval of lamda in a "for" loop.
    So your equation is a quadratic in z1, and z1 is the variable for solution?

    CB
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  5. #5
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    My equation is a quadratic in z1,but when z1 is itself an equatin of beta, then the variable of the main equation is beta.
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