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Math Help - Numerical Analysis Question

  1. #1
    Junior Member
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    Nov 2008
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    Numerical Analysis Question

    How would you solve this problem?

    Show that Max |G(x)| = h^(2)/4
    xj<=x<=x(j+1)

    Where G(x) = (x-jh)(x-(j+1)h)


    j = iteration number
    h = step size

    At first I realize that

    xj = j * h
    x(j+1) = (j+1) * h

    but I still can't reach the final answer h^(2)/4

    Help Please!!
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by Phyxius117 View Post
    How would you solve this problem?

    Show that Max |G(x)| = h^(2)/4
    xj<=x<=x(j+1)

    Where G(x) = (x-jh)(x-(j+1)h)


    j = iteration number
    h = step size

    At first I realize that

    xj = j * h
    x(j+1) = (j+1) * h

    but I still can't reach the final answer h^(2)/4

    Help Please!!
    Can you please clarrify your notation.

    CB
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