Just got this: Kirchoff's voltage law:
the sum of the voltages around a closed citcuit is zero
the voltage drop across:
resistor = iR
inductor = L(di/dt)
capacitor = q/c
can anyone solve this?
To make this easier I just post the whole question on. I dont do physic so I got some troubles with this sort of questions. BTW little 2 means squares
An electric circuit consists of a resistor with a resistance of 6 ohms, a capacitor with a capacitance of 0.04 farads and an inductor with an inductance of 1 henry connected in series with a voltage source of 73cos(4t) volts. Initially the charge on the capacitor is 3 coulombs and the current in the circuit is zero. The current i amps in the circuit at time t seconds satisfies: (d2i/dt2)+6(di/dt)+25i = -292sin(4t)
a) Using Kirchhoff's voltage law, i(0) and q(0), show that the initial current satisfies: (di/dt) = -2 at t = 0
b) Solve the initial value problem, to determine the current in the circuit at any time