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Math Help - Perpendicular Vectors

  1. #1
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    Smile Perpendicular Vectors

    Hello!
    I wasn't sure where to post this thread, but I hope it is the correct place
    It's about perpendicular vectors. I apologise if the question seems a bit messy, as I don't know how to use Latex, but I have tried to do my best.

    The question is:
    The vectors 2x and x+1 are perpendicular for two values of x.
    x-3 5

    a) Write down the quadratic equation which the two values of x must satisfy.
    b) Find the two values of x.

    I would appreciate your help,
    Thanks,
    Amine
    Last edited by Aminekhadir; October 8th 2009 at 08:54 AM. Reason: the vectors are (2x x-3) and (x+1 5). They are two-dimension - not divided by each other. Sorry for the confusion.
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  2. #2
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    Quote Originally Posted by Aminekhadir View Post
    Hello!
    I wasn't sure where to post this thread, but I hope it is the correct place
    It's about perpendicular vectors. I apologise if the question seems a bit messy, as I don't know how to use Latex, but I have tried to do my best.

    The question is:
    The vectors 2x and x+1 are perpendicular for two values of x.
    x-3 5

    a) Write down the quadratic equation which the two values of x must satisfy.
    b) Find the two values of x.
    Your two vectors are \left\langle {2x,x-3} \right\rangle \;\& \,\left\langle {x +1,5} \right\rangle .
    To be perpendicular this must be true: (2x)(x+1)+(x-3)(5)=0.
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