How could one show that: 3n³ – 2n² + 1 ∈ O(n³). 3n³ – 2n² + 1 ∈ Θ(n³).
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by referring to their definitions. 3n³ – 2n² + 1 ∈ O(n³). in the definition, just let the constant be 4 3n³ – 2n² + 1 ∈ Θ(n³). in the definition, let the constant be 2 in omega and let the constant be 4 in big-oh.
Originally Posted by vexiked How could one show that: For : CB
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