derive a theoretical relation between g and D assuming air friction is f = -bv

Hints: mg(t) = mg - bv(t) Newton's Law

g(t) = dv(t) / dt Definition of Acceleratioin

D(t) = integral from t to 0 of v(r)d(r) based on Definition of velocity

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- April 20th 2009, 08:49 PMdixiephysics relation
derive a theoretical relation between g and D assuming air friction is f = -bv

Hints: mg(t) = mg - bv(t) Newton's Law

g(t) = dv(t) / dt Definition of Acceleratioin

D(t) = integral from t to 0 of v(r)d(r) based on Definition of velocity - April 21st 2009, 12:28 AMInvisibleMan
Use the chain rule:

dr=(dr/dt)dt=vdt

Use newton's law to find what is v in regards with g(t), and then plug it instead of v to find the relation between D and g.