Well this is Newtom-Raphson and its convergence depends on where you start and what h(x) actually is. See the Wikipedia article.
CB
Well this is Newtom-Raphson and its convergence depends on where you start and what h(x) actually is. See the Wikipedia article.
CB
You can't. It isn't always. Whether it converges of not depends on the function f, the set of possible values of f (obviously, if where x is required to be real, this will not converge since it must converge to a solution of f(x)= 0 and doesn't have a real solution) and, even when f is such that it can converge, whether it will or not depends on the initial choice of .