Originally Posted by
djmccabie A particle of mass 3kg, moves along the horizontal x-axis under the action of a resultant force FN. Its velocity V m/s at time t s.
v=12t-3t²
a) given that the particle is at the origin O when t=1, find an expression for the displacement of the particle from O at the time t s.
b) Find the acceleration of the particle at time t s.
c) Find the power of the force F when t=1.5
right for part a I think i am supposed to integrate v so i do
∫12t-3t² dt (Is this correct? as in am i supposed to write dt? or dx?)
this gives me the result x=6t²-t³ where x = displacement
Is this the answer?
For part b do i differentiate the original equation?
No sure how to do part C
Any help welcome =]