A particle of mass 3kg, moves along the horizontal x-axis under the action of a resultant force FN. Its velocity V m/s at time t s.
a) given that the particle is at the origin O when t=1, find an expression for the displacement of the particle from O at the time t s.
b) Find the acceleration of the particle at time t s.
c) Find the power of the force F when t=1.5
right for part a I think i am supposed to integrate v so i do
∫12t-3t² dt (Is this correct? as in am i supposed to write dt? or dx?)
this gives me the result x=6t²-t³ where x = displacement
Is this the answer?
For part b do i differentiate the original equation?
No sure how to do part C
Any help welcome =]
You're perfectly right about parts a and b, with a) you need to integrate with t going from 0 to 1.
For part c) you need to use The equation F=ma where F is the force, m is mass and a is acceleration.
Hope that helps.
For Part C the Power is given by
Originally Posted by hairymclairy
Where p is power v is velocity and f is force at time t
Hope this adds to that help (Giggle)
thanks for helping. So before i attempt part c, are the answers to parts a and b:
b) A= 12-6t
where you said t going from 0 to 1, are these the limits to put on the integral?
also would the answer to part c be 101.25W ?