If a 10N force, acting in the direction of the vector (1, 1), moves an object from P(-2, 1) to Q(5, 6), calculate the work done. The distance is in metres.
The work formula is W = F dot D = |F||d|Cos(theta)
Please and thanks
If a 10N force, acting in the direction of the vector (1, 1), moves an object from P(-2, 1) to Q(5, 6), calculate the work done. The distance is in metres.
The work formula is W = F dot D = |F||d|Cos(theta)
Please and thanks
I hope this reply doesn't come too late ...
1. Calculate the vector $\displaystyle \vec F$ with $\displaystyle |\vec F| = 10$:
$\displaystyle \vec F = 10\cdot (1,1)\cdot \dfrac1{|(1,1)|} = (5\sqrt{2}\ ,\ 5\sqrt{2})$
2. Calculate the vector
$\displaystyle \overrightarrow{PQ} = \vec d =(5-(-2), 6-1) = (7, 5)$
3. As you've stated the work is
$\displaystyle W=\vec F \cdot \vec d$ That means:
$\displaystyle W = (5\sqrt{2}\ ,\ 5\sqrt{2}) \cdot (7, 5)=60\sqrt{2} \approx 84.85\ Nm$