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Math Help - Chemical engineering...

  1. #1
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    Chemical engineering...

    20million litres per day (MLD) of a conservative substance, with a concentration of 10mg/L is released into a stream having an upstream flow of 50 MLD and a substance concentration of 3mg/L. Assumin g complete mixing:

    what is the concentration in ppm just downstream?
    what is the mass flow rate of the substance in kg/day passing just downstream?
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  2. #2
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    Quote Originally Posted by Haris View Post
    20million litres per day (MLD) of a conservative substance, with a concentration of 10mg/L is released into a stream having an upstream flow of 50 MLD and a substance concentration of 3mg/L. Assumin g complete mixing:

    what is the concentration in ppm just downstream?
    what is the mass flow rate of the substance in kg/day passing just downstream?
    The concentration just down stream is a weighted average of the two flows (upstream and released)

    c = \frac{20\times 10 + 50\times 3}{70} = 5 mg/L

    For part 2 you just need to multiply flow by concentration

    m = (50 + 20) \times 10^6 \times 5 = 350 \times 10^6 mg/day

    Now there are 10^6 mg in a kg so the mass flow just downstream is 350 kg per day.

    Hope this helps.
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