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  1. #1
    Senior Member euclid2's Avatar
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    physics help

    Consider the earth-moon system. The earth has Me = 5.98 X 10^{24} kg, Re = 6.378 X 10^6 m, Ie = 0.331 Me X Re^2, and Tday = 86164 sec (with respect to fixed stars). The moon has Mm = 7.35 X 10 kg^{22}, Torbit = 27.3 days (with respect to fixed stars, called the siderial period as opposed to the lunar month), and is Dem = 3.84 X 10^8 m from the center of the earth. Approximate the earth as lying at the center of mass of the system, and ignore the contribution of the moon’s spin to its angular momentum. Also ignore any complications due to the presence of the sun.

    The two bodies exert tidal forces on each other, which are strong enough to have slowed the moon’s spin so that it always presents the same face to the earth. These tidal forces have the same effect on the earth: the drag of moving the earth through the ocean’s tides reduces earth’s spin angular momentum and dissipates energy.
    a.
    What is the effect of the tides: consider the variables of angular momentum about the center of the earth and rotational kinetic energy. What happens to each of these for the earth, the moon, and the earth-moon system?
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  2. #2
    Member TheMasterMind's Avatar
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    Quote Originally Posted by euclid2 View Post
    Consider the earth-moon system. The earth has Me = 5.98 X 10^{24} kg, Re = 6.378 X 10^6 m, Ie = 0.331 Me X Re^2, and Tday = 86164 sec (with respect to fixed stars). The moon has Mm = 7.35 X 10 kg^{22}, Torbit = 27.3 days (with respect to fixed stars, called the siderial period as opposed to the lunar month), and is Dem = 3.84 X 10^8 m from the center of the earth. Approximate the earth as lying at the center of mass of the system, and ignore the contribution of the moonís spin to its angular momentum. Also ignore any complications due to the presence of the sun.

    The two bodies exert tidal forces on each other, which are strong enough to have slowed the moonís spin so that it always presents the same face to the earth. These tidal forces have the same effect on the earth: the drag of moving the earth through the oceanís tides reduces earthís spin angular momentum and dissipates energy.
    a.
    What is the effect of the tides: consider the variables of angular momentum about the center of the earth and rotational kinetic energy. What happens to each of these for the earth, the moon, and the earth-moon system?
    It appears based on gravitational attractions there is going to be two tides per day

    Now consider the following

    height \rightarrow \frac{atidal}{g}<br />

    atidal=\Delta g_{moon}=GM_m \frac{1}{(D_{em}+R_e)^2} - \frac{1}{D^2_{em}}=-\frac{2GM_mR_e}{D^3_{em}}=10^{-7}g

    When D_{em}=3.84 * 10^8 m

    This produces tides about 1m high taking into consideration

    R_e=6.378 * 10^6
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