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Math Help - Is this Right? Circular Motion Problem

  1. #1
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    Is this Right? Circular Motion Problem

    Is my answer right?

    A coin with a diameter of 2.4cm is dropped on edge onto a horizontal surface. The coin starts out with an initial angular speed of 18 rad/s and rolls in a straight line without slipping. If the rotation slows with an angular accleration of magnitude 1.9 rad/s^2, how far does the coin roll before coming to a rest?

    Using the equation:

    \omega^{2}=\omega^{2}_{0}+2\alpha \Delta \theta where \omega and \omega_{0} are the final and initial angular speeds respectively; \alpha is the angular acceleration; and \Delta \theta is the angular displacement.

    0=(18)^{2}+2(-1.9)\Delta \theta

    So \Delta \theta = 85.26 \text{rad}.

    Now \Delta \theta = \dfrac{\Delta s}{r} where \Delta s is the change in arc length and r is the radius.

    85.26=\dfrac{\Delta s}{0.012}

    So \Delta s=1.023 \text{m}. Is this right?
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  2. #2
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    looks fine to me
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