I'm currently doing this java application to find the time of intersection of 2 moving objects in a 2D vector space.
Description: Object A moves in a straight line with a constant velocity with a circular sensor of known radius. This circular sensor is centered at object A and a detection occurs when object B crossed the sensor radius. Object B on the other hand, rotates continuously around a known point.
The time of detection is calculated using the formula below:
X^2 + Y^2 = R^2
where X and Y are the x and y coordinates of the location at which a detection occurs. And R is the radius of the sensor of object A.
All the positional and angular information of the 2 objects are known except for the time of detection.
After working out the long and tedious workings, it was found that terms like tcos (wt) and tsin (wt) emerged in the equation and Laplace transformation was applied to change everything to the S-domain.
1.) Can Laplace transformation be applied in this case?
2.) How do i find infomation on how to find the roots of a polynomial in S-domain that has a degree of 6?
3.) How to convert the value of s into the correct value in the time-domain?
4.) Is it possible that someone can shed some light about how i should go about tackling this issue?? Like advices, previous posts or some links where i can read up?
Sorry for the abruptness in the description, I hope to hear some advices from the experts in this forum. Thank you in advance.
Thank you for your reply, I would very much agree with you because the laplace equation that I have arrived in results in a polynomial of degree 6, which makes it difficult to solve.
Does your numerical approach refer to plotting the function out and then use either newton's method or other meothds to estimate the root when the function crosses 0?
You are looking for a root of , where is the distance between the sensor and the target, and is the detection range (in fact the smallest positive root, there may be more than one or zero if the target never crosses the detection boundary, and assuming that at ).
(plotting f(x) is always a good idea, that way at least you have an idea where the root lies, and often a graphical solution is good enough)