Well assuming that beam is in equilibrium, there must be zero moments, and also zero total force in all directions. In this case there is only forces in 1 direction, the vertical.
So, yes. You have a beam which is 2m long. Let's imagine that the far left is A, and the far right is B. So length AB = 2m.
Imagine that the wire at B is the one with a force of 180N.
Then the wire at A will have an upwards force, which creates a torque about point B. This torque will be clockwise, and that's why it's negative.
Then there's the monkey. The monkey has mass 50kg, and hence it has a weight .
The weight of the monkey will cause an anticlockwise torque about B, given by where d is the distance between the monkey and B.
Now we know that the sum of the moments about B must be zero, hence:
And we also know that the sum of the forces is zero, hence:
Using the last equation, you can get a value for , and if you substitute that value into the 2nd to last equation, you can get a value for , and that's everything!
One major assumption here is that the beam itself has zero/negligible weight.