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Math Help - 2nd order PDE charcteristics... help please! :S

  1. #1
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    2nd order PDE charcteristics... help please! :S

    hi all, sorry again for the thousands of stupid questions! :P but heres another one...



    ok i said for part (a) that the PDE is a hyperbolic type and so has two sets of real characteristics. and that the characteristics are

    then for part (b) i used the coordinates:


    which leads to the equation:


    but then i am stuck... how can i get the 'general solution' from this, i think i am heading in the right direction, but i am not sure.

    any help would be greatly appreciated!

    thanks

    Sarah
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  2. #2
    hpe
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    Quote Originally Posted by sarahisme View Post
    but then i am stuck... how can i get the 'general solution' from this, i think i am heading in the right direction, but i am not sure.

    any help would be greatly appreciated!

    thanks

    Sarah
    The next step is to express y in terms of \epsilon and \tau.

    Covering all the bases, are we
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  3. #3
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    Quote Originally Posted by hpe View Post
    The next step is to express y in terms of \epsilon and \tau.

    Covering all the bases, are we
    lol, sure am

    hmm i think i did my orginal conversion a little bit wrong, i now get that:


    then putting in y gives:


    is that just then solved as:



    but this doesnt seem to work when i put it back into the orginal PDE.... :S
    Last edited by sarahisme; October 2nd 2006 at 07:58 PM.
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