Thread: another vertors and oblique triangles problem

1. another vertors and oblique triangles problem

someone help on this can? pls.....
solve the given problems

in lifting a heavy piece of equipment from the mud, a cable from a crane exerts a vertical force of 6500N, and a cable from a truck exerts a force of 8300N at 10.0 degree above the horizontal. find the resultant of these forces.

2. Originally Posted by danielwu
someone help on this can? pls.....
solve the given problems

in lifting a heavy piece of equipment from the mud, a cable from a crane exerts a vertical force of 6500N, and a cable from a truck exerts a force of 8300N at 10.0 degree above the horizontal. find the resultant of these forces.
Let us draw a coordinate system.
With the origion of the point on which the two forces are applied.
The vertial force of 6500 N can be expressed in vector form as,
6500j.
The truck on the left with an 8300 N for at a 10 degree angle above the x-axis needs a polar angle conversion. The x-coordinate is 8300 cos (10) = 8174. The y-coordinate is 8300 sin (10) = 1441.
Thus, in vector form it can be expressed as,
8174i+8174j.

Now you add then and have a resultant.

3. Originally Posted by ThePerfectHacker
Let us draw a coordinate system.
With the origion of the point on which the two forces are applied.
The vertial force of 6500 N can be expressed in vector form as,
6500j.
The truck on the left with an 8300 N for at a 10 degree angle above the x-axis needs a polar angle conversion. The x-coordinate is 8300 cos (10) = 8174. The y-coordinate is 8300 sin (10) = 1441.
Thus, in vector form it can be expressed as,
8174i+8174j.

Now you add then and have a resultant.
i got the answers behind the book as 11000N, 44 degree above horizontal

but by doing your method i couldnt understand and get the correct answers.
pls help me understand further. thanks